document.write( "Question 161015: At 9am two bicyclists heading in opposite directions pass eachother on a bicycle path. The bike heading north is riding 8km/hour FASTER than the bike heading south. At 1030 they are 36km apart. Find the two bikes rates and show you got your answers \n" ); document.write( "
Algebra.Com's Answer #118645 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! At 9am two bicyclists heading in opposite directions pass each other on a bicycle path. The bike heading north is riding 8km/hour FASTER than the bike heading south. At 1030 they are 36km apart. Find the two bikes rates and show you got your answers \n" ); document.write( ": \n" ); document.write( "Let s = speed of the southbound bike \n" ); document.write( "then \n" ); document.write( "(s+8) = speed of the northbound bike \n" ); document.write( ": \n" ); document.write( "Find the travel time (since they met) of the bikes: 10;30 - 9:00 = 1.5 hrs \n" ); document.write( ": \n" ); document.write( "Write a distance equation; Dist = time * speed \n" ); document.write( ": \n" ); document.write( "South dist = north dist = 36 mi \n" ); document.write( "1.5s + 1.5(s+8) = 36 \n" ); document.write( "1.5s + 1.5s + 12 = 36 \n" ); document.write( "3s = 36 - 12 \n" ); document.write( "s = \n" ); document.write( "s = 8 mph speed of the southbound bike \n" ); document.write( "and \n" ); document.write( "8 + 8 = 16 mph speed of the northbound bike \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the total distance \n" ); document.write( "1.5(8) + 1.5(16) = \n" ); document.write( "12 + 24 = 36 \n" ); document.write( " |