document.write( "Question 160966: Amanda has some pennies, nickels, dimes, and quarters in her piggy bank. There is more than $1.50 and less than $2.25. Using the clues, determine how much money Amanda has.
\n" ); document.write( "-there are 4 times as many nickels as quarters
\n" ); document.write( "-there are twice as many quarters as dimes
\n" ); document.write( "-there is an equal number of pennies and dimes\r
\n" ); document.write( "\n" ); document.write( "Thank you for you help!!
\n" ); document.write( "

Algebra.Com's Answer #118631 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Amanda has some pennies, nickels, dimes, and quarters in her piggy bank. There is more than $1.50 and less than $2.25. Using the clues, determine how much money Amanda has.
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( ":
\n" ); document.write( "\"-there are 4 times as many nickels as quarters\"
\n" ); document.write( "n = 4q
\n" ); document.write( ":
\n" ); document.write( "\"-there are twice as many quarters as dimes\"
\n" ); document.write( "q = 2d
\n" ); document.write( ":
\n" ); document.write( "\"-there is an equal number of pennies and dimes\"
\n" ); document.write( "p = d
\n" ); document.write( ":
\n" ); document.write( "Write a total$ equation within the given range
\n" ); document.write( ".01p + .05n + .10d + .25q = 2.00
\n" ); document.write( ":
\n" ); document.write( "try to get everything in terms of d:
\n" ); document.write( "In the 1st equation, substitute 2d or q (from the 2nd equation)
\n" ); document.write( "n = 4(2d)
\n" ); document.write( "n = 8d
\n" ); document.write( ":
\n" ); document.write( "Substitute:
\n" ); document.write( ".01d + .05(8d) + .10d + .25(2d) = 2.00
\n" ); document.write( ".01d + .40d + .10d + .50d = 2
\n" ); document.write( "1.01d = 2
\n" ); document.write( "d = \"2%2F1.01\" obviously not a solution (has to be an integer)
\n" ); document.write( ":
\n" ); document.write( "Make a solution by multiplying 1.01 * 2, so the total is $2.02, then we have:
\n" ); document.write( "d = \"2.02%2F1.01\"
\n" ); document.write( "d = 2 dimes
\n" ); document.write( "then
\n" ); document.write( ".01(2) + .40(2) + .10(2) + .50(2) = 2
\n" ); document.write( ".02 + .80 + .20 + 1.00 = $2.02
\n" ); document.write( ":
\n" ); document.write( "Find the number of each coin using d = 2:
\n" ); document.write( "p = d; 2 pennies
\n" ); document.write( "n = 8d: 16 nickels
\n" ); document.write( "d = 2 dimes
\n" ); document.write( "q = 2d; 4 quarters
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Confirm solution from this:
\n" ); document.write( ".01(2) + .05(16) + .10(2) + .25(4) =
\n" ); document.write( ".02 + .80 + .20 + 1.00 = $2.02 is Amanda's total
\n" ); document.write( ":
\n" ); document.write( "There are probably other ways to do this. Did this make sense to you? \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );