document.write( "Question 23197: Hi,
\n" ); document.write( "I have been working this problem and I can not get the proper answer. Please help!
\n" ); document.write( "Whitney invested $38,000, part at 2% and part at 12%. If the total interest at the end of the year is $2,760, how much did she invest at 2%?\r
\n" ); document.write( "\n" ); document.write( "Thank you
\n" ); document.write( "Sherri
\n" ); document.write( "

Algebra.Com's Answer #11862 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Let amount invested at 2% be \"x\"
\n" ); document.write( "Then amount invested at 12% is \"38000-x\"
\n" ); document.write( "Interest at 2% is 0.02x
\n" ); document.write( "Interest at 12% is 0.12(38000-x)= 4560-o.12x
\n" ); document.write( "EQUATION:
\n" ); document.write( " Int. at 2% + Int. at 12% = $2760
\n" ); document.write( " 0.02x + 4560-0.12x = 2760
\n" ); document.write( " 2x + 456000- 12x = 276000
\n" ); document.write( " -10x = -180000
\n" ); document.write( " x = $18,000 (amount invested at 2%)
\n" ); document.write( " 38000-x = $20000 (amount invested at 12%)\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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