document.write( "Question 23197: Hi,
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document.write( "I have been working this problem and I can not get the proper answer. Please help!
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document.write( "Whitney invested $38,000, part at 2% and part at 12%. If the total interest at the end of the year is $2,760, how much did she invest at 2%?\r
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document.write( "Thank you
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document.write( "Sherri \n" );
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Algebra.Com's Answer #11862 by stanbon(75887) ![]() You can put this solution on YOUR website! Let amount invested at 2% be \"x\" \n" ); document.write( "Then amount invested at 12% is \"38000-x\" \n" ); document.write( "Interest at 2% is 0.02x \n" ); document.write( "Interest at 12% is 0.12(38000-x)= 4560-o.12x \n" ); document.write( "EQUATION: \n" ); document.write( " Int. at 2% + Int. at 12% = $2760 \n" ); document.write( " 0.02x + 4560-0.12x = 2760 \n" ); document.write( " 2x + 456000- 12x = 276000 \n" ); document.write( " -10x = -180000 \n" ); document.write( " x = $18,000 (amount invested at 2%) \n" ); document.write( " 38000-x = $20000 (amount invested at 12%)\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |