Algebra.Com's Answer #118610 by KnightOwlTutor(293)  You can put this solution on YOUR website! \n" );
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document.write( " Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc | \n" );
document.write( "Equation describes a sloping line. For any \n" );
document.write( " equation ax+by+c = 0, slope is .- X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 0/1 = 0.
- Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 0/-1 = 0.
- Slope is -1/-1 = 1.
- Equation in slope-intercept form: y=1*x+0.
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document.write( " Solved by pluggable solver: SOLVE quadratic equation with variable | \n" );
document.write( "Quadratic equation (in our case ) has the following solutons: \n" );
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document.write( " For these solutions to exist, the discriminant should not be a negative number. \n" );
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document.write( " First, we need to compute the discriminant : . \n" );
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document.write( " Discriminant d=0 is zero! That means that there is only one solution: . \n" );
document.write( " Expression can be factored:  \n" );
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document.write( " Again, the answer is: 0, 0.\n" );
document.write( "Here's your graph: \n" );
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