document.write( "Question 23195: Please help me solve this equation: \"+16+%5E+%282+-+x%29+%2B+16%5E%28+x%29+=+40++\".
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Algebra.Com's Answer #11858 by dkspoet(13)\"\" \"About 
You can put this solution on YOUR website!
16^(2-x)+16^x = 40
\n" ); document.write( "16^2/16^x+16^x = 40
\n" ); document.write( "256+16^2x = 40(16^x)
\n" ); document.write( "16^2x-40(16^x)+256 = 0
\n" ); document.write( "16^2x-8(16^x)-32(16^x)+256 = 0
\n" ); document.write( "16^x(16^x-8)-32(16^x-8) = 0
\n" ); document.write( "(16^x-32)(16^x-8) = 0
\n" ); document.write( "16^x = 32 or 16^x = 8
\n" ); document.write( "x = 5/4 or x = 3/4
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