document.write( "Question 160850: The perimeter of a rectangular room is 37 3/5 ft. The width is 6 4/5 feet. Find the length.\r
\n" ); document.write( "\n" ); document.write( "I know the formula is p=2l + 2w but the fractions and information are confusing \n" ); document.write( "

Algebra.Com's Answer #118572 by gonzo(654) $\"\"$ $\"About$

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P = 2*L + 2*W
\n" ); document.write( "37+(3/5) = 2*L + 2*(6+(4/5))
\n" ); document.write( "making the improper fraction into proper fraction gets
\n" ); document.write( "188/5 = 2*L + (2*(34/5))
\n" ); document.write( "this becomes
\n" ); document.write( "188/5 = 2*L + (2*34)/5
\n" ); document.write( "multiplying both sides of the equation by 5 to remove the denominators and
\n" ); document.write( "the equation becomes
\n" ); document.write( "188 = 2*5*L + (2*34)
\n" ); document.write( "which becomes
\n" ); document.write( "188 = 10*L + 68
\n" ); document.write( "subtracting 68 from both sides and equation becomes
\n" ); document.write( "188-68 = 10*L
\n" ); document.write( "which becomes
\n" ); document.write( "120 = 10*L
\n" ); document.write( "which becomes L = 12
\n" ); document.write( "-----
\n" ); document.write( "substituting in the original equation gets
\n" ); document.write( "37 + (3/5) = (2*12) + 2*(6 + 4/5)
\n" ); document.write( "converting to proper fraction and equation becomes
\n" ); document.write( "188/5 = 2*12 + 2*(34/5)
\n" ); document.write( "multiplying both sides by 5 to remove the denominators and equation becomes
\n" ); document.write( "188 = 2*5*12 + 2*34
\n" ); document.write( "which becomes
\n" ); document.write( "188 = 120 + 68
\n" ); document.write( "which becomes
\n" ); document.write( "188 = 188
\n" ); document.write( "so answer is good. \n" ); document.write( "

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