document.write( "Question 160846: Train A travels 60mph
\n" ); document.write( "Train B travels 70mph
\n" ); document.write( "Train A reaches a spot at 6:15, Train B reaches same spot at 6:27, when will train B catch up to train A? \n" ); document.write( "
Algebra.Com's Answer #118571 by gonzo(654)\"\" \"About 
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the trains will meet after they have both traveled the same distance.
\n" ); document.write( "train A has to do that distance in T minutes
\n" ); document.write( "train B has to do that distance in (T-12) minutes because train B started 12 minutes later (6:27 - 6:15).
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\n" ); document.write( "the equation for train A is T * 60 = D
\n" ); document.write( "the equation for train B is (T - 12) * 70 = D
\n" ); document.write( "since they both = D, then they are equal to each other.
\n" ); document.write( "T * 60 = (T - 12) * 70
\n" ); document.write( "solve this equation as follows:
\n" ); document.write( "T * 60 = (70 * T) - (70 * 12)
\n" ); document.write( "60*T = 70*T - 840
\n" ); document.write( "840 = 10*T
\n" ); document.write( "T = 84 minutes.
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\n" ); document.write( "in 84 minutes, train A will have traveled 84/60 * 60 = 84 miles.
\n" ); document.write( "in 84 minutes, train B will have traveled 72/60 * 70 = 84 miles.
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\n" ); document.write( "division by 60 was necessary to convert minutes to hours.\r
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