document.write( "Question 160809: since the beginning of the month, a local reservoir has been losing water in a linear fashion. On the 12th of the month the resrviour held 200 million gallons of water, and on the 21st of the month it held only 164 million gallons. Assuming this continues, express the number of gallons as a function of time,t, where t is the number of days elapsed since the beginning of the month. Determine when the tank will be empty. \n" ); document.write( "
Algebra.Com's Answer #118559 by AksharTech(1)![]() ![]() You can put this solution on YOUR website! Since the reservoir has been losing water in a LINEAR fashion, the expresion of the function will be similar to the equation of a straight line. \n" ); document.write( "Standard equation of a straight line is as follows: \n" ); document.write( "y = mx + C\r \n" ); document.write( "\n" ); document.write( "Replace y by the quantity of water and x by the time elapsed i.e. 't'. \n" ); document.write( "quantity of water = mt + C ......(eq-1)\r \n" ); document.write( "\n" ); document.write( "You get two equations by plugging the values provided in the question for Quantity of water and time elapsed. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve this pair of linear equations. \n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You get m = -4 and C = 248 \n" ); document.write( "Plug-in these values in eq-1 shown above. So you get the number of gallons as a function of time,t. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug-in 0 for the quantity of water in this equation to determine when the tank will be empty. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Therefore the tank will be empty after 62 days. ....(Answer#2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |