document.write( "Question 160779: Find the angles of a triangle where one angle is three times a second angle and six times the third angle.
\n" ); document.write( "I think the variables should be:
\n" ); document.write( "x = one angle
\n" ); document.write( "3x = second angle
\n" ); document.write( "6x = third angle
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Algebra.Com's Answer #118535 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Not quite
\n" ); document.write( "The first angle is 3 times the second. You have the second angle as 3 times the first.
\n" ); document.write( "Likewise, the first angle is 6 times the third. You have the thrid angle as 6 times the first.\r
\n" ); document.write( "\n" ); document.write( "The angles should be \"x+%2C+x%2F3%2C+x%2F6\"
\n" ); document.write( "You know the sum of the angles is 180 (since this is a triangle)
\n" ); document.write( "\"180+=+x+%2B+x%2F3+%2B+x%2F6\"
\n" ); document.write( "\"180+=+%286x+%2B+2x+%2B+x%29%2F6\"
\n" ); document.write( "\"1080+=+9x\"
\n" ); document.write( "\"120+=+x\"}
\n" ); document.write( "So the other angles are 120/3 = 40
\n" ); document.write( "and 120/6 = 20\r
\n" ); document.write( "\n" ); document.write( "Does 120+40+20 = 180?
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