document.write( "Question 160779: Find the angles of a triangle where one angle is three times a second angle and six times the third angle.
\n" );
document.write( "I think the variables should be:
\n" );
document.write( "x = one angle
\n" );
document.write( "3x = second angle
\n" );
document.write( "6x = third angle \n" );
document.write( "
Algebra.Com's Answer #118535 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! Not quite \n" ); document.write( "The first angle is 3 times the second. You have the second angle as 3 times the first. \n" ); document.write( "Likewise, the first angle is 6 times the third. You have the thrid angle as 6 times the first.\r \n" ); document.write( "\n" ); document.write( "The angles should be \n" ); document.write( "You know the sum of the angles is 180 (since this is a triangle) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So the other angles are 120/3 = 40 \n" ); document.write( "and 120/6 = 20\r \n" ); document.write( "\n" ); document.write( "Does 120+40+20 = 180? \n" ); document.write( " \n" ); document.write( " |