document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=160756>Question 160756</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x+2y+z=1<BR>\n" );
document.write( "2x+3y+2z=0<BR>\n" );
document.write( "-x-3y+3z=1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118522 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the first equation:<BR>\n" );
document.write( "z=1-x-2y\r<BR>\n" );
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document.write( "Put this into the second equation:\r<BR>\n" );
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document.write( "2x+3y+2(1-x-2y)=0<BR>\n" );
document.write( "2x+3y+2-2x-4y=0<BR>\n" );
document.write( "-y=-2<BR>\n" );
document.write( "y=2\r<BR>\n" );
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document.write( "If y=2, put that in the third equation:<BR>\n" );
document.write( "-x-3(2)+3(1-x-2(2))=1<BR>\n" );
document.write( "-x-6+3-3x-12=1<BR>\n" );
document.write( "-4x=16<BR>\n" );
document.write( "x=-4\r<BR>\n" );
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document.write( "Now put y=2 and x=-4 into our z from step 1.<BR>\n" );
document.write( "z=1-(-4)-2(2)=1\r<BR>\n" );
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document.write( "Giving solution set  {-4,2,1}. This also can be solved through techniques of linear algebra (Cramer's Rule, RREF, etc). If you need it solved in a way such as that, send me an E-mail to enabla@gmail.com  . </SPAN>\n" );
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