document.write( "Question 160766: I invested $18,000. Part of it was invested at 3% annual simple interst and the rest was invested at 4%. I earned $650 in interest for the year. How much did I invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #118517 by KnightOwlTutor(293)![]() ![]() You can put this solution on YOUR website! Amount invested at 3%=x \n" ); document.write( "Amount invested at 4%=18,000-x\r \n" ); document.write( "\n" ); document.write( "Convert % into decimal format 3%=.03 4%=.04 \n" ); document.write( "The equation is as follows\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".03x+.04(18,000-x)=$650\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the distributive property\r \n" ); document.write( "\n" ); document.write( ".03+720-.04x=650\r \n" ); document.write( "\n" ); document.write( "Subtract 720 from both sides\r \n" ); document.write( "\n" ); document.write( "add the two x terms\r \n" ); document.write( "\n" ); document.write( "-.01x=-70\r \n" ); document.write( "\n" ); document.write( "Divide both terms by -.01\r \n" ); document.write( "\n" ); document.write( "x=$7000 invested at 3%\r \n" ); document.write( "\n" ); document.write( "$18,000-$7,000=$11,000 invested at 4%\r \n" ); document.write( "\n" ); document.write( "Let's double check our answer by calculating the interest generated by each portion and determining whether this amount equals the amount designated in the problem.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".03(7000)+.04(11000)=210+440=650\r \n" ); document.write( "\n" ); document.write( "650=650\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |