document.write( "Question 160767: Lauren has $1000 made up of only ten and twenty dollar bills. She has a total of 75 bills. How many of each kind does she have? \n" ); document.write( "

Algebra.Com's Answer #118516 by KnightOwlTutor(293) $\"\"$ $\"About$

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Let # of $10=x
\n" ); document.write( "Let# of $20=75-x\r
\n" ); document.write( "\n" ); document.write( "Here is the equation\r
\n" ); document.write( "\n" ); document.write( "$10x+$20(75-x)=$1000\r
\n" ); document.write( "\n" ); document.write( "Use the distributive property\r
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\n" ); document.write( "\n" ); document.write( "$10x+$1500-$20x=$1000\r
\n" ); document.write( "\n" ); document.write( "Subtract 1500 from both sides\r
\n" ); document.write( "\n" ); document.write( "add the two x terms\r
\n" ); document.write( "\n" ); document.write( "-$10x=-$500\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by -10
\n" ); document.write( "x=50\r
\n" ); document.write( "\n" ); document.write( "Let's check our answer\r
\n" ); document.write( "\n" ); document.write( "when the number of $10 bills is 50 you have $10(50)=$500\r
\n" ); document.write( "\n" ); document.write( "75-25=50 therefore the $ amount of &20=$500\r
\n" ); document.write( "\n" ); document.write( "$500+$500=$1000 which is the amount of $ that Lauren has.\r
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