document.write( "Question 160747: graph a line with the slope -3 passing through the point(-2,-5) \n" ); document.write( "

Algebra.Com's Answer #118504 by KnightOwlTutor(293) $\"\"$ $\"About$

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We know the general equation of a line is y=mx+B
\n" ); document.write( "we know m=-3
\n" ); document.write( "so our line has the general equation of y=-3x+b\r
\n" ); document.write( "\n" ); document.write( "we can solve for b by plugging in the x,y values into the equation
\n" ); document.write( "-5=(-3)(-2)+b
\n" ); document.write( "-5=6+b
\n" ); document.write( "subtract 6 from both sides
\n" ); document.write( "-11=b\r
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc

Equation $\"3+x+%2B+1+y+=+-11\"$ describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is $\"-a%2Fb+=+-3%2F1\"$ .

X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. -11/3 = -3.66666666666667.
Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is -11/1 = -11.
Slope is -3/1 = -3.
Equation in slope-intercept form: y=-3*x+-11.

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