document.write( "Question 160742This question is from textbook
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document.write( ": at 10:00am a car leaves a house at a rate of 60mi/h. at the same time, another car leaves the same house at a rate of 50mi/h in the opposite direction. at what time will the cars be 330 miles apart? \n" );
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Algebra.Com's Answer #118503 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "First the easy way. You can do it in your head. \r\n" ); document.write( "They are separating at the rate of 60+50 or 110 mi/h. \r\n" ); document.write( "So at that rate it would take them 3 hours to be \r\n" ); document.write( "separated by 330 miles. That would be at 1PM.\r\n" ); document.write( "\r\n" ); document.write( "But your teacher doesn't want you to do it this easy way.\r\n" ); document.write( "So here is the way your teacher wants you to do it:\r\n" ); document.write( "\r\n" ); document.write( "Let t = the number of hours after 10 AM when \r\n" ); document.write( "they will be 330 miles apart\r\n" ); document.write( "\r\n" ); document.write( "Make this DRT-chart:\r\n" ); document.write( "\r\n" ); document.write( " Distance Rate Time\r\n" ); document.write( "1st car \r\n" ); document.write( "2nd car \r\n" ); document.write( "\r\n" ); document.write( "They both travel the same length of time. So fill in\r\n" ); document.write( "t for both times.\r\n" ); document.write( "\r\n" ); document.write( " Distance Rate Time\r\n" ); document.write( "1st car t\r\n" ); document.write( "2nd car t\r\n" ); document.write( "\r\n" ); document.write( "Their rates are 60 and 50, so fill those in for the\r\n" ); document.write( "rates.\r\n" ); document.write( "\r\n" ); document.write( " Distance Rate Time\r\n" ); document.write( "1st car 60 t\r\n" ); document.write( "2nd car 50 t\r\n" ); document.write( "\r\n" ); document.write( "Now use D=RT to fill in the distances:\r\n" ); document.write( "\r\n" ); document.write( " Distance Rate Time\r\n" ); document.write( "1st car 60t 60 t\r\n" ); document.write( "2nd car 50t 50 t\r\n" ); document.write( "\r\n" ); document.write( "Now the sum of the two distances must equal 330 miles.\r\n" ); document.write( "\r\n" ); document.write( "So we have the equation:\r\n" ); document.write( "\r\n" ); document.write( "60t + 50t = 330\r\n" ); document.write( " 110t = 330\r\n" ); document.write( " t = 3\r\n" ); document.write( "\r\n" ); document.write( "So it will take 3 hours after 10AM, or 1PM.\r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |