document.write( "Question 160723This question is from textbook
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document.write( ": The width of a rectangular garden is 3yd more than twice its width. The perimeter of the rectangle is 36yd. What are the width and the length?\r
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document.write( "Any assistance is appreciated. I am the dad and if I can see how this one is done I can figure out the rest. Thank you! \n" );
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Algebra.Com's Answer #118489 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! The length of a rectangular garden is 3yd more than twice its width. The perimeter of the rectangle is 36yd. What are the width and the length? \n" ); document.write( ". \n" ); document.write( "Let w = width \n" ); document.write( "from \"The length of a rectangular garden is 3yd more than twice its width.\" we get: \n" ); document.write( "w+3 = length \n" ); document.write( ". \n" ); document.write( "Since: \n" ); document.write( "length+length+width+width = perimeter \n" ); document.write( "2length+2width = perimeter \n" ); document.write( "2(length+width) = perimeter \n" ); document.write( ". \n" ); document.write( "substituting in our variables and info: \n" ); document.write( "2(length+width) = perimeter \n" ); document.write( "2((w+3)+w) = 36 \n" ); document.write( "2(w+3+w) = 36 \n" ); document.write( "2(2w+3) = 36 \n" ); document.write( "2w+3 = 18 \n" ); document.write( "2w = 15 \n" ); document.write( "w = 7.5 yards (width) \n" ); document.write( ". \n" ); document.write( "length: \n" ); document.write( "w+3 = 7.5+3 = 10.5 yards (length)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |