document.write( "Question 160690: In right triangle ABC, altitude CD is drawn to hypotenuse AB. If CD=6 and AD=9, find DB.\r
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document.write( "PLEASE HELP!, THANKS \n" );
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Algebra.Com's Answer #118485 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! you need to find angle DCA which will allow you to find angle DCB which will allow you to find DB. \n" ); document.write( "you know that CD is 6 and you know that AD is 9. \n" ); document.write( "tangent of DCA equals AD / CD = 9/6 = 1.5 \n" ); document.write( "arctangent of 1.5 = 56.30993247 degrees = DCA \n" ); document.write( "DCA = 56.30993247 degrees. \n" ); document.write( "----- \n" ); document.write( "since ACB is a right angle, then angle DCB = 90 degrees minus DCA = 90 degrees minus 56.30993247 degrees = 33.69006753 degrees. \n" ); document.write( "DCB = 33.69006753 degrees. \n" ); document.write( "----- \n" ); document.write( "tangent of DCB is BD / CD. \n" ); document.write( "since CD is 6, tangent of DCB is BD / 6. \n" ); document.write( "multiplying both sides of the equation by 6 and it becomes \n" ); document.write( "BD = 6 * tangent of DCB = 6 * tangent of 33.69006753 degrees. \n" ); document.write( "solving, BD becomes 4. \n" ); document.write( "BD = 4. \n" ); document.write( "BD and DB are the same line. \n" ); document.write( "----- \n" ); document.write( "answer is DB = 4. \n" ); document.write( "----- \n" ); document.write( "i solved for BC and for AC to get the other 2 sides of the triangle and then solved for c^2 = a^2 + b^2 to prove the answer was correct and it was confirmed.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |