document.write( "Question 160678: I don't understand how to set up this problem in order to solve it because the book examples do not break it up the same way.
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document.write( "Dave invested half his money at 5%, one-third his money at 4%, and the rest of his money at 3.5%. If his total annual investment income was $530, how much had he invested? \n" );
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Algebra.Com's Answer #118484 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! first thing you have to do is find out what the rest is. \n" ); document.write( "several ways to do it. \n" ); document.write( "one way is as follows: \n" ); document.write( "1/2 + 1/3 + x = 1 \n" ); document.write( "solve for x. \n" ); document.write( "easiest way is to multiply both sides of the equation by 6 to remove the denominators. \n" ); document.write( "equation becomes \n" ); document.write( "3 + 2 + 6*x = 6 \n" ); document.write( "6*x = 6 - 3 - 2 = 1 \n" ); document.write( "x = 1/6 \n" ); document.write( "----- \n" ); document.write( "to see if that's correct, add up 1/2 + 1/3 + 1/6 to see if it adds up to 1. \n" ); document.write( "1/3 is the same as 2/6. \n" ); document.write( "1/2 is the same as 3/6 \n" ); document.write( "so 2/6 + 3/6 + 1/6 = 6/6 = 1. \n" ); document.write( "x = 1/6 is good. \n" ); document.write( "----- \n" ); document.write( "you know what the total income each year is. \n" ); document.write( "it's $530. \n" ); document.write( "----- \n" ); document.write( "now you know that: \n" ); document.write( "1/2 of the money is invested at 5%. \n" ); document.write( "1/3 of the money is invested at 4%. \n" ); document.write( "1/6 of the money is invested at 3.5% \n" ); document.write( "----- \n" ); document.write( "if 1/2 of the money is invested at 5%, then the amount of income from 1/2 of the money at the end of the year is 5% times (1/2 of the money). \n" ); document.write( "this also means that 4% times (1/3 of the money) give you the amount of income from 1/3 of the money at the end of the year. \n" ); document.write( "this also means that 3.5% times (1/6) of the money) gives you the amount of income from 1/6 of the money \n" ); document.write( "----- \n" ); document.write( "let y = total amount of money invested. \n" ); document.write( "let $530 = total income from money invested. \n" ); document.write( "equation becomes: \n" ); document.write( "5%*y*1/2 + 4%*y*1/3 + 3.5%*y*1/6 = $530 \n" ); document.write( "----- \n" ); document.write( "this is the same as (5%*y)/2 + (4%*y)/3 + (3.5%*y)/6 = $530. \n" ); document.write( "----- \n" ); document.write( "to get the interest rate you have to divide by 100%. \n" ); document.write( "5% / 100% = .05 \n" ); document.write( "4% / 100% = .04 \n" ); document.write( "3.5% / 100% = .035 \n" ); document.write( "----- \n" ); document.write( "you substitute interest rate for % interest and the equation becomes \n" ); document.write( "----- \n" ); document.write( "(.05*y)/2 + (.04*y)/3 + (.035*y)/6 = $530. \n" ); document.write( "multiplying both sides of the equation by 6 to remove the denominators, and the equation becomes \n" ); document.write( "3*.05*y + 2*.04*y + .035*y = 6*$530 \n" ); document.write( "which becomes \n" ); document.write( ".15*y + .08*y + .035*y = $3180 \n" ); document.write( "which becomes \n" ); document.write( ".265*y = $3180 \n" ); document.write( "which becomes \n" ); document.write( "y = $3180/.265 which equals $12000. \n" ); document.write( "----- \n" ); document.write( "to prove that the answer is correct, you substitute $12000 for y and solve the original equation after you converted from % to rate. \n" ); document.write( "that equation is .05*y*(1/2) + .04*y*(1/3) + .035*y*(1/6) = $530. \n" ); document.write( "which becomes \n" ); document.write( ".05*12000*(1/2) + .04*12000*(1/3) + .035*12000*(1/6) = $530. \n" ); document.write( "which becomes \n" ); document.write( "$300 + $160 + $70 = $530 \n" ); document.write( "which becomes \n" ); document.write( "$530 = $530 \n" ); document.write( "which proves the equation is good. \n" ); document.write( "----- \n" ); document.write( "your answer is total money invested is $12000.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |