document.write( "Question 160692: At a sale, all CDs are one price and all tapes are another price. Three CDs and two tapes cost $72. One CD and three tapes cost $52. What are the prices of one CD and one tape?\r
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document.write( "So far I've got:\r
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document.write( "3c + 2t =72
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document.write( "c + 3t =52\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #118481 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! That's a good start. \n" ); document.write( ". \n" ); document.write( "3c + 2t =72 \n" ); document.write( " c + 3t =52 \n" ); document.write( ". \n" ); document.write( "Now, let's multiply both sides of the bottom equation by -3: \n" ); document.write( " 3c + 2t = 72 \n" ); document.write( "-3c - 9t =-156 \n" ); document.write( ". \n" ); document.write( "Combine both equations: \n" ); document.write( " 3c + 2t = 72 \n" ); document.write( "-3c - 9t =-156 \n" ); document.write( "------------------- \n" ); document.write( " -7t = -84 \n" ); document.write( " t = 12 (dividing both sides by -7) \n" ); document.write( ". \n" ); document.write( "Using the above, we can plug it into equation 2: \n" ); document.write( " c + 3t =52 \n" ); document.write( " c + 3(12) =52 \n" ); document.write( " c + 36 =52 \n" ); document.write( " c = 16 \n" ); document.write( ". \n" ); document.write( "Solution: \n" ); document.write( "tapes: $12 \n" ); document.write( "cd: $16 \n" ); document.write( " |