document.write( "Question 160692: At a sale, all CDs are one price and all tapes are another price. Three CDs and two tapes cost $72. One CD and three tapes cost $52. What are the prices of one CD and one tape?\r
\n" ); document.write( "\n" ); document.write( "So far I've got:\r
\n" ); document.write( "\n" ); document.write( "3c + 2t =72
\n" ); document.write( "c + 3t =52\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #118481 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
That's a good start.
\n" ); document.write( ".
\n" ); document.write( "3c + 2t =72
\n" ); document.write( " c + 3t =52
\n" ); document.write( ".
\n" ); document.write( "Now, let's multiply both sides of the bottom equation by -3:
\n" ); document.write( " 3c + 2t = 72
\n" ); document.write( "-3c - 9t =-156
\n" ); document.write( ".
\n" ); document.write( "Combine both equations:
\n" ); document.write( " 3c + 2t = 72
\n" ); document.write( "-3c - 9t =-156
\n" ); document.write( "-------------------
\n" ); document.write( " -7t = -84
\n" ); document.write( " t = 12 (dividing both sides by -7)
\n" ); document.write( ".
\n" ); document.write( "Using the above, we can plug it into equation 2:
\n" ); document.write( " c + 3t =52
\n" ); document.write( " c + 3(12) =52
\n" ); document.write( " c + 36 =52
\n" ); document.write( " c = 16
\n" ); document.write( ".
\n" ); document.write( "Solution:
\n" ); document.write( "tapes: $12
\n" ); document.write( "cd: $16
\n" ); document.write( "
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