document.write( "Question 160552This question is from textbook
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document.write( ": A store sells regular coffe for $4 a pound and a gourmet coffee for $7 a pound. To get rid of 40 pounds of the gourmet coffee, the shopkeeper plans to make a gourmet blend to sell for $5 a pound. How many pounds of regular coffee should be used? \n" );
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Algebra.Com's Answer #118450 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=amount of regular coffee needed\r \n" ); document.write( "\n" ); document.write( "Now we know that the cost of the regular coffee (4x) plus the cost of the gourmet coffee(7*40) has to equal the cost of the final mixture (5(40+x)). So: \n" ); document.write( "4x+7*40=5(40+x) get rid of parens (distributive) \n" ); document.write( "4x+280=200+5x subtract 200 and also 4x from each side \n" ); document.write( "4x-4x+280-200=200-200+5x-4x collect like terms \n" ); document.write( "80=x or \n" ); document.write( "x=80 lbs -----------------amount of regular coffee needed \n" ); document.write( "CK \n" ); document.write( "4*80+7*40=5*120 \n" ); document.write( "320+280=600 \n" ); document.write( "600=600\r \n" ); document.write( "\n" ); document.write( "Hope this helps-----ptaylor \n" ); document.write( " |