document.write( "Question 160552This question is from textbook
\n" ); document.write( ": A store sells regular coffe for $4 a pound and a gourmet coffee for $7 a pound. To get rid of 40 pounds of the gourmet coffee, the shopkeeper plans to make a gourmet blend to sell for $5 a pound. How many pounds of regular coffee should be used? \n" ); document.write( "
Algebra.Com's Answer #118450 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=amount of regular coffee needed\r
\n" ); document.write( "\n" ); document.write( "Now we know that the cost of the regular coffee (4x) plus the cost of the gourmet coffee(7*40) has to equal the cost of the final mixture (5(40+x)). So:
\n" ); document.write( "4x+7*40=5(40+x) get rid of parens (distributive)
\n" ); document.write( "4x+280=200+5x subtract 200 and also 4x from each side
\n" ); document.write( "4x-4x+280-200=200-200+5x-4x collect like terms
\n" ); document.write( "80=x or
\n" ); document.write( "x=80 lbs -----------------amount of regular coffee needed
\n" ); document.write( "CK
\n" ); document.write( "4*80+7*40=5*120
\n" ); document.write( "320+280=600
\n" ); document.write( "600=600\r
\n" ); document.write( "\n" ); document.write( "Hope this helps-----ptaylor
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