document.write( "Question 160629This question is from textbook technical mathematics with calculus
\n" ); document.write( ": Spacecraft A is over Houstion at noon on a certain day and traveling at a rate of 275 km/h. Spacecraft B, attemting to overtake and dock with A, is over Houston at 1:15pm and is traveling in the same direction as A, at 444 km/h. At what time will B overtake A? At what distance from Houston? \n" ); document.write( "
Algebra.Com's Answer #118446 by checkley77(12844)\"\" \"About 
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275t=444(t-1.25)
\n" ); document.write( "275t=444t-555
\n" ); document.write( "275t-444t=-555
\n" ); document.write( "-169t=-555
\n" ); document.write( "t=-555/-169
\n" ); document.write( "t=3.284 hours they will meet.
\n" ); document.write( "Proof:
\n" ); document.write( "275*3.284=444(3.284-1.25)
\n" ); document.write( "903.1=444(2.034)
\n" ); document.write( "903.1=903.1
\n" ); document.write( "
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