document.write( "Question 160629This question is from textbook technical mathematics with calculus
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document.write( ": Spacecraft A is over Houstion at noon on a certain day and traveling at a rate of 275 km/h. Spacecraft B, attemting to overtake and dock with A, is over Houston at 1:15pm and is traveling in the same direction as A, at 444 km/h. At what time will B overtake A? At what distance from Houston? \n" );
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Algebra.Com's Answer #118446 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 275t=444(t-1.25) \n" ); document.write( "275t=444t-555 \n" ); document.write( "275t-444t=-555 \n" ); document.write( "-169t=-555 \n" ); document.write( "t=-555/-169 \n" ); document.write( "t=3.284 hours they will meet. \n" ); document.write( "Proof: \n" ); document.write( "275*3.284=444(3.284-1.25) \n" ); document.write( "903.1=444(2.034) \n" ); document.write( "903.1=903.1 \n" ); document.write( " |