document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=160573>Question 160573</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Stella's catering is planning a wedding reception. The bride and groom would like to serve a nut mixture containing 25% peanuts. Stella has available mixtures that are either 40% or 10% peanuts. How much of each type should be mixed to get a 10-lb mixture that is 25% peanuts? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118403 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The total quantity is 10lbs. This amount never changes only the composition.<BR>\n" );
document.write( "X=# lbs of 40%peanuts<BR>\n" );
document.write( "10-x==# lbs of 10%peanuts\r<BR>\n" );
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document.write( "Convert % to decimal format=40%=.4, 10%=.1 25%=.25\r<BR>\n" );
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document.write( "The linear equation is as follows\" .40x+.1(10-x)=10(.25)\r<BR>\n" );
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document.write( "To make it easier multiply each term by a hundred. It doesn't change the equation it just makes it easier to solve.\r<BR>\n" );
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document.write( "40x+(10)(10-x)=10(25)\r<BR>\n" );
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document.write( "Use the distributive propery\r<BR>\n" );
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document.write( "40x+100-10x=250\r<BR>\n" );
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document.write( "Subtract 10x from 40x\r<BR>\n" );
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document.write( "30x+100=250\r<BR>\n" );
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document.write( "Subtract 100 from both sides of the equation\r<BR>\n" );
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document.write( "30x=150\r<BR>\n" );
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document.write( "divide both sides by 30\r<BR>\n" );
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document.write( "x=5\r<BR>\n" );
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document.write( "5lbs of 40% peanuts are needed<BR>\n" );
document.write( "10-5=5lbs of 10% peanuts are needed \r<BR>\n" );
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document.write( "To double check your answer you plug in the values in the above equation<BR>\n" );
document.write( "40x+(10)(10-x)=10(25)\r<BR>\n" );
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document.write( ".4(5)+.1(5)=10(.25)\r<BR>\n" );
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document.write( "2.+.5=2.5\r<BR>\n" );
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document.write( " </SPAN>\n" );
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