document.write( "Question 160428: Factor using ac method
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Algebra.Com's Answer #118337 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"4z%5E2-5z-6\", we can see that the first coefficient is \"4\", the second coefficient is \"-5\", and the last term is \"-6\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"4\" by the last term \"-6\" to get \"%284%29%28-6%29=-24\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-24\" (the previous product) and add to the second coefficient \"-5\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-24\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-24\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,4,6,8,12,24\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-4,-6,-8,-12,-24\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-24\".\r
\n" ); document.write( "\n" ); document.write( "1*(-24)
\n" ); document.write( "2*(-12)
\n" ); document.write( "3*(-8)
\n" ); document.write( "4*(-6)
\n" ); document.write( "(-1)*(24)
\n" ); document.write( "(-2)*(12)
\n" ); document.write( "(-3)*(8)
\n" ); document.write( "(-4)*(6)\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"-5\":\r
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First NumberSecond NumberSum
1-241+(-24)=-23
2-122+(-12)=-10
3-83+(-8)=-5
4-64+(-6)=-2
-124-1+24=23
-212-2+12=10
-38-3+8=5
-46-4+6=2
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"3\" and \"-8\" add to \"-5\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"3\" and \"-8\" both multiply to \"-24\" and add to \"-5\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"-5z\" with \"3z-8z\". Remember, \"3\" and \"-8\" add to \"-5\". So this shows us that \"3z-8z=-5z\".\r
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\n" ); document.write( "\n" ); document.write( "\"4z%5E2%2Bhighlight%283z-8z%29-6\" Replace the second term \"-5z\" with \"3z-8z\".\r
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\n" ); document.write( "\n" ); document.write( "\"%284z%5E2%2B3z%29%2B%28-8z-6%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"z%284z%2B3%29%2B%28-8z-6%29\" Factor out the GCF \"z\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"z%284z%2B3%29-2%284z%2B3%29\" Factor out \"2\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28z-2%29%284z%2B3%29\" Combine like terms. Or factor out the common term \"4z%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"4z%5E2-5z-6\" factors to \"%28z-2%29%284z%2B3%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by FOILing \"%28z-2%29%284z%2B3%29\" to get \"4z%5E2-5z-6\" or by graphing the original expression and the answer (the two graphs should be identical).
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