document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=160413>Question 160413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given: square root of (10x+6)(-) square root of (4x+4) = 2<BR>\n" );
document.write( "Solution:<BR>\n" );
document.write( "1.   I isolated sq rt. of (10+6) = 2 +sq.rt.(4x+4)<BR>\n" );
document.write( "2.   sq. rt. of (10x+6)^2 = {2 + (4x+4)}^2<BR>\n" );
document.write( "3.   get rid of sq. rt. 10x +6 = 4 + 4sq.rt.of (4x+4) + 4x+4<BR>\n" );
document.write( "4.   10x +6 = 4x + 8 + sq.rt.(4x+4)mult.4<BR>\n" );
document.write( "5.   6x -2 = sq.rt.(4x+4) mult.4<BR>\n" );
document.write( "6.   (6x-2)^2 = {sq. rt. (4x +4)mult. 4}^2<BR>\n" );
document.write( "7.   36x^2 - 24x +4 = 16 (4x+4)<BR>\n" );
document.write( "8.   36x^2 - 24x +4 = 64x + 64<BR>\n" );
document.write( "9.   36x^2- 88x - 60= 0<BR>\n" );
document.write( "After this I am having difficulty to come up with the solution. Where did I go wrong? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118331 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118331\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> your work seems fine so far\r<BR>\n" );
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document.write( "dividing by 4 __ 9x^2-22x-15=0\r<BR>\n" );
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document.write( "using quadratic formula __ x=(22±32)/18 __ x=(11±16)/9 __ x=-5/9 and x=3 </SPAN>\n" );
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