document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=160398>Question 160398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could someone please show me how to multiply and simplify this equation.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=36b%2F%283b%5E2-24b%2B48%29 ALIGN=MIDDLE  ALT=\"36b%2F%283b%5E2-24b%2B48%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283b-12%29%2F6b ALIGN=MIDDLE  ALT=\"%283b-12%29%2F6b\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118318 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> factor out 3 from 3b^2-24b+48 to get 3(b^2-8b+16)\r<BR>\n" );
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document.write( "(b^2-8b+16)can be factored by finding 2 numbers multiplied together gives a product of 16 but when added together gives you -8\r<BR>\n" );
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document.write( "It is obvious that the numbers must be both negative (-)(-)=(+)\r<BR>\n" );
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document.write( "A likely choice is -4   (-4)(-4)=16 and (-4)+(-4)=-8\r<BR>\n" );
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document.write( "Therefore (b^2-8b+16)=(b-4)(b-4)\r<BR>\n" );
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document.write( "[36b/3(b-4)(b-4)][3(b-4)/6b]  you divided 36b by 6b and get 6(3(b-4)/3(b-4)(b-4)\r<BR>\n" );
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document.write( "simplify by canceling out the 3(b-4) terms in the numerator and denominator and you are left with 6/b-4<BR>\n" );
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