document.write( "Question 160379: If Cecil was four times as old as Bin 8 years ago and if Cecil will be twice as old as Bin 8 years hence, what are their ages now? \n" ); document.write( "
Algebra.Com's Answer #118313 by KnightOwlTutor(293) You can put this solution on YOUR website! X is Bin's current age\r \n" ); document.write( "\n" ); document.write( "8 years ago Cecil was four n Bin's age. \r \n" ); document.write( "\n" ); document.write( "(X-8)4=Cecil's age\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In eight years Cecil will be 2n Bin's age.\r \n" ); document.write( "\n" ); document.write( "(x-8)4+16=2(x+8) \n" ); document.write( "You need to add 16 to keep the number of years equal on both sides, there is a difference of 16 years on one side of the equation\r \n" ); document.write( "\n" ); document.write( "Use the distributive property\r \n" ); document.write( "\n" ); document.write( "4x-32+16=2x+16 \n" ); document.write( "4x-16=2x+16\r \n" ); document.write( "\n" ); document.write( "add 16 to each side\r \n" ); document.write( "\n" ); document.write( "4x=2X+32\r \n" ); document.write( "\n" ); document.write( "subtract 2X from each side\r \n" ); document.write( "\n" ); document.write( "2X=32\r \n" ); document.write( "\n" ); document.write( "x=16\r \n" ); document.write( "\n" ); document.write( "16-8= age Bin when Cecil was 4times his age\r \n" ); document.write( "\n" ); document.write( "Bin was 8 and Cecil was 32 in eight years Cecil will be 48 and Bin will be\r \n" ); document.write( "\n" ); document.write( "24\r \n" ); document.write( "\n" ); document.write( "Thus Bin is now 16 and Cecil is ow 40\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "add \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |