document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=160347>Question 160347</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of an angle is 21 degrees more than twice its supplement. Find the measure of each angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118302 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     The measure of an angle is 21 degrees more than twice its supplement. Find the measure of each angle?<BR>\n" );
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document.write( "If two angles are supplementary, the sum of the two angles equals 180 degrees.<BR>\n" );
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document.write( "Let x = angle<BR>\n" );
document.write( "then<BR>\n" );
document.write( "180-x = supplement of angle<BR>\n" );
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document.write( "x = 2(180-x)+21<BR>\n" );
document.write( "x = 360-2x+21<BR>\n" );
document.write( "x = 381-2x<BR>\n" );
document.write( "3x = 381<BR>\n" );
document.write( "x = 127 degrees (angle)<BR>\n" );
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document.write( "supplement:<BR>\n" );
document.write( "180-x = 180-127 = 53 degrees (supplement)<BR>\n" );
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