document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=160343>Question 160343</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -11x = 395 + y<BR>\n" );
document.write( "14y = -634 - 10x \r<BR>\n" );
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document.write( "I need to solve this system of linear equations using any method. I'd like to see the steps and the correct answer. I'm not sure which method would be the easiest and I'm just stuck. Thank you for all your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118300 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118300\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> subtracting 395 from 1st eqn __ -11x-395=y\r<BR>\n" );
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document.write( "substituting into 2nd eqn __ 14(-11x-395)=-634-10x __ -154x-5530=-634-10x\r<BR>\n" );
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document.write( "-144x=4896 __ x=-34\r<BR>\n" );
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document.write( "substituting __ -11(-34)-395=y __ -21=y </SPAN>\n" );
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