document.write( "Question 160297: mary invests $24,000 in two seperate accounts. one earns 6% simple interest and the other 9%. if she earned a total of $1740, how much did she invest at each rte? \n" ); document.write( "

Algebra.Com's Answer #118259 by jojo14344(1513) $\"\"$ $\"About$

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\n" ); document.write( "Let \"x\", amount invested at 9%. So \"24000-x\" is the amount inv. at 6%.
\n" ); document.write( "Putting into eqn:
\n" ); document.write( " $\"0.09x%2B0.06%2824000-x%29=1740\"$ working eqn
\n" ); document.write( " $\"0.09x%2B1440-0.06x=1740\"$
\n" ); document.write( " $\"0.03x=1740-1440\"$
\n" ); document.write( " $\"0.03x=300\"$
\n" ); document.write( " $\"cross%280.03%29x%2Fcross%280.03%29=cross%28300%2910000%2Fcross%280.03%29\"$
\n" ); document.write( " $\"x=10000\"$ --------------> amt invested at 9%
\n" ); document.write( " $\"24000-10000=14000\"$ -----> amt invested at 6%
\n" ); document.write( "check via working eqn:
\n" ); document.write( " $\"0.09%2A10000%2B0.06%2A14000=1740\"$
\n" ); document.write( " $\"900%2B840=1740\"$
\n" ); document.write( " $\"1740=1740\"$
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

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