document.write( "Question 160302This question is from textbook Algerbra and Trigonometry structure and method
\n" ); document.write( ": two ships leave port, one sailing east and the other south. Some time later they are 17 miles apart, with the eastbound ship 7 miles further from the port than the southbound ship. how far is each from port? \n" ); document.write( "

Algebra.Com's Answer #118256 by jojo14344(1513) $\"\"$ $\"About$

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\n" ); document.write( "As you can sketch they form a right triangle ---> Ship1 goes East and Ship2 goes South with 17 miles apart (hypotenuse).
\n" ); document.write( "Then, $\"S%5B2%5D\"$ is $\"x\"$ miles fromt the port. (adjacent), that depends of course which angle of inclination. For argument sake we put adjacent.
\n" ); document.write( "Also, $\"S%5B1%5D\"$ is $\"7%2Bx\"$ miles farther from the port than $\"S%5B2%5D\"$ (opposite)
\n" ); document.write( "By Pythagorean Theorem:
\n" ); document.write( " $\"hyp%5E2=adj%5E2%2Bopp%5E2\"$ --------------> working eqn
\n" ); document.write( " $\"17%5E2=x%5E2%2B%28x%2B7%29%5E2\"$
\n" ); document.write( " $\"x%5E2%2Bx%5E2%2B14x%2B49-289=0\"$
\n" ); document.write( " $\"2x%5E2%2B14x-240=0\"$ divide whole eqn by 2
\n" ); document.write( " $\"x%5E2%2B7x-120=0\"$ perfect square
\n" ); document.write( " $\"%28x%2B15%29%28x-8%29=0\"$
\n" ); document.write( " $\"x=-15\"$ , $\"x=8\"$
\n" ); document.write( "use $\"x=8miles\"$ , distance of $\"S%5B2%5D\"$ from the port
\n" ); document.write( " $\"7%2B8=15miles\"$ , distance of $\"S%5B1%5D\"$ from the port
\n" ); document.write( "check via working eqn:
\n" ); document.write( " $\"17%5E2=8%5E2%2B15%5E2\"$
\n" ); document.write( " $\"289=64%2B225\"$
\n" ); document.write( " $\"289=289\"$
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo\n" ); document.write( "

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