document.write( "Question 160286: One alloy is one part copper to three parts tin. A second alloy is one part copper to four parts tin. How much of the second alloy should be combined with 24 pounds of the first alloy to obtain a new alloy that is two parts copper to seven parts tin? \n" ); document.write( "
Algebra.Com's Answer #118239 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! One alloy is one part copper to three parts tin. A second alloy is one part copper to four parts tin. How much of the second alloy should be combined with 24 pounds of the first alloy to obtain a new alloy that is two parts copper to seven parts tin? \n" ); document.write( ". \n" ); document.write( "Let x = pounds of second alloy to be added \n" ); document.write( ". \n" ); document.write( "From: \"One alloy is one part copper to three parts tin.\" \n" ); document.write( "we know that: \n" ); document.write( "total of four parts \n" ); document.write( ".25 is copper \n" ); document.write( ".75 is tin \n" ); document.write( ". \n" ); document.write( "From: \"A second alloy is one part copper to four parts tin.\" \n" ); document.write( "total of four parts \n" ); document.write( ".20 is copper \n" ); document.write( ".80 is tin \n" ); document.write( ". \n" ); document.write( "We want: \n" ); document.write( "2/9 copper \n" ); document.write( "7/9 tin \n" ); document.write( ". \n" ); document.write( "Just consider the copper (we could have considered tin or copper -- didn't matter): \n" ); document.write( ".25(24) + .20x = (2/9)(24+x) \n" ); document.write( ".25(24) + .20x = (2/9)(24+x) \n" ); document.write( "6 + .20x = (2/9)(24+x) \n" ); document.write( "54 + 1.8x = (2)(24+x) \n" ); document.write( "54 + 1.8x = 48+2x \n" ); document.write( "6 = .2x \n" ); document.write( "30 pounds = x \n" ); document.write( " \n" ); document.write( " |