document.write( "Question 160275: If 19 kilos of gold loses 1 kilo and 10 kilos of silver loses 1 kilo when weighted in water, find the weight of the gold in a bar of gold and silver weighing 106 kilos in air and 99 kilos in water? \n" ); document.write( "

Algebra.Com's Answer #118234 by Edwin McCravy(20055) $\"\"$ $\"About$

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If 19 kilos of gold loses 1 kilo and 10 kilos of silver loses 1 kilo when weighted in water, find the weight of the gold in a bar of gold and silver weighing 106 kilos in air and 99 kilos in water?
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document.write( "Let  = the no. of kilos of gold in the bar \r\n" );
document.write( "(when weighed in air).\r\n" );
document.write( "Let  = the no. of kilos of silver in the bar \r\n" );
document.write( "(when weighed in air).\r\n" );
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document.write( ">>...a bar...weighing 106 kilos in air...<<\r\n" );
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document.write( "Therefore one equation is\r\n" );
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document.write( ">>...19 kilos of gold loses 1 kilo and 10 kilos of \r\n" );
document.write( "silver loses 1 kilo when weighted in water...<<\r\n" );
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document.write( "Therefore\r\n" );
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document.write( "1 kilo of gold loses  kilo and 1 kilo of \r\n" );
document.write( "silver loses  kilo when weighted in water.\r\n" );
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document.write( "Therefore\r\n" );
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document.write( " = the no. of kilos the gold in the \r\n" );
document.write( "bar weighs in water.\r\n" );
document.write( " = the no. of kilos the silver in the \r\n" );
document.write( "bar weighs in water.\r\n" );
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document.write( ">>...a bar...weighing...99 kilos in water?\r\n" );
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document.write( "Therefore\r\n" );
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document.write( "is the other equation.\r\n" );
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document.write( "Simplifying it:\r\n" );
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document.write( "Multiply through by the LCD of 190:\r\n" );
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document.write( "That can be divided through by 3 getting\r\n" );
document.write( "only whole numbers:\r\n" );
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document.write( "So we have this system:\r\n" );
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document.write( "Solve that by substitution or elimination\r\n" );
document.write( "and get:\r\n" );
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document.write( "Edwin

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