document.write( "Question 160268: I have an exponential equation - not sure if I went about it in the right way or not...\r
\n" ); document.write( "\n" ); document.write( "(125/8)^x+1 = (2/5)^x-1\r
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\n" ); document.write( "\n" ); document.write( "for want of a better way of doing things I decided to make both values inside the parentheses to be divided by the same thing thus\r
\n" ); document.write( "\n" ); document.write( "(625/40)^x+1 = (16/40)^x-1\r
\n" ); document.write( "\n" ); document.write( "then decided to combine to get the exponentials from x+1 - (x-1) to = 2\r
\n" ); document.write( "\n" ); document.write( "and then combining the other to give me a final answer of (609/40)^2\r
\n" ); document.write( "\n" ); document.write( "Is this correct or how else should I do this please? \n" ); document.write( "

Algebra.Com's Answer #118230 by Edwin McCravy(20056) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Notice that  and that  so \r\n" );
document.write( "so replace  by :\r\n" );
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document.write( "Multiply exponents on the left:\r\n" );
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document.write( "Distribute: \r\n" );
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document.write( "Now observe that on the right the base  is the \r\n" );
document.write( "reciprocal of the base on the left, and the reciprocal\r\n" );
document.write( "is the  power, so write  on the right as :\r\n" );
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document.write( "Multiply the exponents on the right:\r\n" );
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document.write( "Distribute:\r\n" );
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document.write( "Since both sides are powers of the same base, and\r\n" );
document.write( "since that base is neither 0 nor 1, we may equate\r\n" );
document.write( "the exponents and drop the bases:\r\n" );
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document.write( "Edwin

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