document.write( "Question 2700: Can someone smarter than me answer this question?\r
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document.write( "Thank You\r
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document.write( "You have administered a standardized test of manual dexterity to two groups of 10 semi skilled workers. One of these two groups of workers will be employed by you to work in a warehouse with many fragile items. The higher the manual dexterity of a worker the less likelihood that worker will break significant inventory. Because of a unique contract you must hire all 10 employees from one of the two groups and none of the employees from the other. \r
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document.write( "Group A Scores
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document.write( "98
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document.write( "85
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document.write( "30
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document.write( "66
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document.write( "99
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document.write( "95
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document.write( "57
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document.write( "
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document.write( "62
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document.write( "
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document.write( "99
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document.write( "
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document.write( "100
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document.write( "Group B Scores
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document.write( "64
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document.write( "81
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document.write( "62
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document.write( "88
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document.write( "82
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document.write( "79
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document.write( "90
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document.write( "81
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document.write( "
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document.write( "85
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document.write( "
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document.write( "79
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document.write( "You must decide which group to choose. Choose at least two measures of central tendency and at least one measure of dispersion for each group and use those to make your choice. Be sure to justify your choice
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document.write( "
Algebra.Com's Answer #1182 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! Find the mean and median of each set of data \n" ); document.write( "Then find the variation (or standard deviation) for the spread.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Look in your maths books for the process for these - i am going to bed in a minute :-)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jon \n" ); document.write( " \n" ); document.write( " |