document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22002>Question 22002</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm in algebra one is 7th grade, and i hope you can help. I'm doing these two problems and i have no idea how to solve them.\r<BR>\n" );
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document.write( "Here are the directions: Set up each inequality and show all work. Written explanations should be in complete sentences. \r<BR>\n" );
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document.write( "Jesse has 27 coins, some of which are dimes and the rest are quarters. Altogether the coins are worth more than $4.20. At least how many of the coins are quarters? At most how many are dimes? \r<BR>\n" );
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document.write( "Mr. A and Mrs. N are leaving school and traveling in opposite directions.  If Mrs. N runs 2 miles per hour and Mr. A runs 5 miles per hour, how long would it take them to be at least 15 miles away from each other? \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11817 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11817\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let number of quarters \"x\".<BR>\n" );
document.write( "Then number of dimes is \"27-x\"<BR>\n" );
document.write( "Value of quarters is (25)x cents<BR>\n" );
document.write( "Value of dimes is (10)(27-x) = 270-10x cents<BR>\n" );
document.write( "INEQUALITY:<BR>\n" );
document.write( "  Value of quarters + Value of dimes >= 420 cents<BR>\n" );
document.write( "        25x + 270-10x >=420<BR>\n" );
document.write( "             15x >= 150<BR>\n" );
document.write( "               x >= 10 (number of quarters)<BR>\n" );
document.write( "          27-x <= 17 (number of dimes)\r<BR>\n" );
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document.write( "d= rt<BR>\n" );
document.write( "A data: Let distance be \"x\"; rate is 5; time is x/5<BR>\n" );
document.write( "N data: Then distance is \"15-x\" ; rate is 2; time is (15-x)/2<BR>\n" );
document.write( "INEQUALITY(?):<BR>\n" );
document.write( "Whatever the distance is between them the times are equal, so:<BR>\n" );
document.write( "  time of \"A\" = time of \"N\"<BR>\n" );
document.write( "   x/5 = (15-x)/2<BR>\n" );
document.write( "  2x= 5(15-x)<BR>\n" );
document.write( "  2x = 75-5x<BR>\n" );
document.write( "  7x = 75<BR>\n" );
document.write( "   x = (75/7) miles (A's distance\"<BR>\n" );
document.write( "Since \"A\" runs at 5 mph divide her distance by 5 to get:<BR>\n" );
document.write( "   75/7/5 = 15/7 = 2 (1/7) hrs.<BR>\n" );
document.write( "Therefore for them to be \"at least 15 miles apart\" their<BR>\n" );
document.write( "time must be >=2 1/7 hrs.\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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