document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=160222>Question 160222</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The function p(d)=1+d/33, gives the pressure, in atmospheres (atm), at a depth d in the sea (d is in feet).  Note that p(0)=1 atm, p(33)=2, and so on.  Find the pressure at 110 ft.\r<BR>\n" );
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document.write( "The pressure at 110 ft. is _____ atm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118165 by </B><A HREF=/tutors/aboutme.mpl?userid=gonzo><B>gonzo(654)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gonzo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118165\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> it looks like all you have to do is set d = 110<BR>\n" );
document.write( "then p(110) = 1 + (110/33)<BR>\n" );
document.write( "this becomes 1 + 3 and one third = 4 and 1 third = 4.333333333..... = 4.33 atm rounded to the nearest hundredth.<BR>\n" );
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