document.write( "Question 160229: if steven can mix 20 drinks in 5 minutes.sue can mix 20 drinks in 10 minutes. jack can mix 20 drinks in 15 minutes.how much time will it take all three of them working together to mix the 20 drinks \n" ); document.write( "
Algebra.Com's Answer #118161 by ptaylor(2198)\"\" \"About 
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\n" ); document.write( "Let x= amount of time it takes all three working together to mix 20 drinks
\n" ); document.write( "Steven mixes drinks at the rate of 20/5 or 4 drinks per min
\n" ); document.write( "Sue mixes drinks at the rate of 20/10 or 2 drinks per min
\n" ); document.write( "Jack mixes drinks at the rate of 20/15 or 1 1/3=4/3 drinks per min\r
\n" ); document.write( "\n" ); document.write( "Together, the three mixes drinks at the rate of 4+2+4/3 drinks per min or:
\n" ); document.write( "12/3 + 6/3 +4/3 = 22/3 drinks per min. So or equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "(22/3)x=20 multiply each side by 3
\n" ); document.write( "22x=60 divide each side by 22
\n" ); document.write( "x=2.73 min------------------------------------ans
\n" ); document.write( "CK
\n" ); document.write( "Steven: 4*2.73=10.9 drinks
\n" ); document.write( "Sue: 2*2.73=5.46 drinks
\n" ); document.write( "Jack: (4/3)*2.73=3.64 drinks
\n" ); document.write( "10.9+5.46+3.63=20
\n" ); document.write( "20=20\r
\n" ); document.write( "\n" ); document.write( "Hope this helps--ptaylor\r
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