document.write( "Question 21644: An elevator went from the bottom to the top at 240m tower, remained there for 12 sec, and returned to the bottom in an elapsed time of 2 minutes. I fthe elevator traveled 1 m/s faster on the way down, find its speed going up. \n" ); document.write( "
Algebra.Com's Answer #11812 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Time up + time down = 120 sec -12 sec = 108 sec
\n" ); document.write( "Up data: distance = 240 m; rate= x; time= 240/x
\n" ); document.write( "Down data: dist = 240 m; rate = x+1; time = 240/(x+1)
\n" ); document.write( "EQUATION:
\n" ); document.write( " Time up + Time down = 108 sec
\n" ); document.write( " 240/x + 240/(x+1) = 108
\n" ); document.write( " 1/x + 1/(x+1) = .45
\n" ); document.write( " 2x +1= .45(x^2+x)
\n" ); document.write( " 9x^2-31x - 20 =0
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"9x%5E2%2B31x%2B-20+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2831%29%5E2-4%2A9%2A-20=1681\".
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\n" ); document.write( " Discriminant d=1681 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-31%2B-sqrt%28+1681+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%2831%29%2Bsqrt%28+1681+%29%29%2F2%5C9+=+0.555555555555556\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2831%29-sqrt%28+1681+%29%29%2F2%5C9+=+-4\"
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\n" ); document.write( " Quadratic expression \"9x%5E2%2B31x%2B-20\" can be factored:
\n" ); document.write( " \"9x%5E2%2B31x%2B-20+=+9%28x-0.555555555555556%29%2A%28x--4%29\"
\n" ); document.write( " Again, the answer is: 0.555555555555556, -4.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+9%2Ax%5E2%2B31%2Ax%2B-20+%29\"

\n" ); document.write( "\n" ); document.write( "Looks like rate up is 0.55... meters/sec
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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