document.write( "Question 160192: The equation of the line that goes through the point(3,4) and is parallel to the line going through the points (-6,6) and (1,3) can be written in the form y=mx+b where
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\n" ); document.write( "I am having difficulty with the second part only m=-3/7 \n" ); document.write( "
Algebra.Com's Answer #118119 by nerdybill(7384)\"\" \"About 
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The equation of the line that goes through the point(3,4) and is parallel to the line going through the points (-6,6) and (1,3) can be written in the form y=mx+b where
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\n" ); document.write( "You already discover that the slope of a line going through the points (-6,6) and (1,3) is
\n" ); document.write( "m = -3/7
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\n" ); document.write( "Now, you have a \"point\" (3,4) and a \"slope\" (-3/7).
\n" ); document.write( "Plug it all into the \"point-slope\" form of a line:
\n" ); document.write( "y – y1 = m(x – x1)
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\n" ); document.write( "y – 4 = (-3/7)(x – 3)
\n" ); document.write( "7y – 28 = (-3)(x – 3)
\n" ); document.write( "7y – 28 = -3x + 9
\n" ); document.write( "7y = -3x + 37
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\n" ); document.write( "Your answer then is:
\n" ); document.write( "y = (-3/7)x + (37/7)
\n" ); document.write( "m= -3/7
\n" ); document.write( "b= 37/7\r
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