document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=160152>Question 160152</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A collection of 1 cent (pennies), 5 cent (pickels) and 10 cent (dimes) totals 2.12.00. The total number of coins is 42 and there are twice as many 5 cent (nickels0 as 10 cent (dimes). How many of each kind are there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118105 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118105\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X=number of dimes<BR>\n" );
document.write( "2X=number of nickels\r<BR>\n" );
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document.write( "42-x-2x=number of pennies\r<BR>\n" );
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document.write( ".10x+.05(2x)+.01(42-3x)=2.12\r<BR>\n" );
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document.write( "To make this expression easier to deal with multiply each term by 100\r<BR>\n" );
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document.write( "10x+10x+42-3x=212\r<BR>\n" );
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document.write( "Simplify by combining like terms\r<BR>\n" );
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document.write( "(10+10-3)x+42=212\r<BR>\n" );
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document.write( "17x+42=212\r<BR>\n" );
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document.write( "Subract 42 from both sides\r<BR>\n" );
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document.write( "17X=170\r<BR>\n" );
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document.write( "X=10=number of dimes<BR>\n" );
document.write( "2X=20=number of nickels\r<BR>\n" );
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document.write( "42-3x=12=number of pennies\r<BR>\n" );
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document.write( "Let's check our answer 10(.1)=$1.00<BR>\n" );
document.write( "                       20(.05)=$1.00<BR>\n" );
document.write( "                       12(.01)=$0.12\r<BR>\n" );
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document.write( "add together and come up with $2.12\r<BR>\n" );
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document.write( " </SPAN>\n" );
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