document.write( "Question 160119: can someone please help me with this problem:\r
\n" ); document.write( "\n" ); document.write( "Evaluate the function at the given value of the independent variable and simplify.\r
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\n" ); document.write( "\n" ); document.write( "f(x) = x^3 + 3 / x^2 - 3 ; f(3)
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Algebra.Com's Answer #118094 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
f(x) = x^3 + 3 / x^2 - 3 ; f(3)
\n" ); document.write( "f(3)=3^3+3/3^2-3
\n" ); document.write( "f(3)=27+3/9-3
\n" ); document.write( "f(3)=27+1/3-3
\n" ); document.write( "f(3)=(27*3+1+3*3)/3
\n" ); document.write( "f(3)=(81+1+9)/3
\n" ); document.write( "f(3)=91/3 answer.
\n" ); document.write( "OR:
\n" ); document.write( "f(3)=3^3+3/(3^2-3)
\n" ); document.write( "f(3)=27+3/(9-3)
\n" ); document.write( "f(3)=27+3/6
\n" ); document.write( "f(3)=(27*6+3)/6
\n" ); document.write( "f(3)=(162+3)/6
\n" ); document.write( "f(3)=165/6
\n" ); document.write( "f(3)=55/2 answer.
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