document.write( "Question 160093: 3p+2(p+4)=-12\r
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document.write( "4x+rt=x+16\r
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document.write( "2(pq+4)=3x-pq\r
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document.write( "1+3(5x-2)=5(x+1) \n" );
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Algebra.Com's Answer #118081 by checkley77(12844) ![]() You can put this solution on YOUR website! 3p+2(p+4)=-12 \n" ); document.write( "3p+2p+8=-12 \n" ); document.write( "5p=-12-8 \n" ); document.write( "5p=-20 \n" ); document.write( "p=-20/5 \n" ); document.write( "p=-4 answer. \n" ); document.write( "Proof: \n" ); document.write( "3*-4+2(-4+4)=-12 \n" ); document.write( "-12+0=-12 \n" ); document.write( "-12=-12 \n" ); document.write( "------------------------------------------- \n" ); document.write( "4x+rt=x+16 \n" ); document.write( "4x-x=16-rt \n" ); document.write( "3x=16-rt \n" ); document.write( "x=(16-rt)/3 answer. \n" ); document.write( "Proof: \n" ); document.write( "4(16-rt)/3+rt=(16-rt)/3+16 \n" ); document.write( "(64-4rt)/3+rt=(16-rt)/3+16 \n" ); document.write( "(64-4rt+3rt)/3=(16-rt+16*3)/3 \n" ); document.write( "(64-rt)/3=(16-rt+48)/3 \n" ); document.write( "(64-rt)/3=(64-rt)/3 \n" ); document.write( "--------------------------------------------- \n" ); document.write( "2(pq+4)=3x-pq \n" ); document.write( "2pq+8=3x-pq \n" ); document.write( "3x=2pq+pq+8 \n" ); document.write( "3x=3pq+8 \n" ); document.write( "x=pq+8/3 answer. \n" ); document.write( "Proof: \n" ); document.write( "2(pq+4)=3(pq+8/3)-pq \n" ); document.write( "2pq+8=3pq+24/3-pq \n" ); document.write( "2pq+8=2pq+8 \n" ); document.write( "---------------------------------------- \n" ); document.write( "1+3(5x-2)=5(x+1) \n" ); document.write( "1+15x-6=5x+5 \n" ); document.write( "15x-5x=5+6-1 \n" ); document.write( "10x=10 \n" ); document.write( "x=10/10 \n" ); document.write( "x=1 answer. \n" ); document.write( "proof: \n" ); document.write( "1+3(5*1-2)=5(1+1) \n" ); document.write( "1+3(5-2)=5*2 \n" ); document.write( "1+3*3=10 \n" ); document.write( "1+9=10 \n" ); document.write( "10=10 \n" ); document.write( " \n" ); document.write( " |