document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=160111>Question 160111</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A contractor orders 8 cubic yards of premixed cement, all of which is  to be used to pour a patio that will be 4 inches thick. If the length of the patio is specified to be twice the width, what will be the patio dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118077 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118077\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8yd^3=8*3*3*3=216 ft^3<BR>\n" );
document.write( "Volume=l*w*d (length, width, depth)<BR>\n" );
document.write( "216=2w*w*1/3<BR>\n" );
document.write( "216=2w^2/3<BR>\n" );
document.write( "2w*2=216*3<BR>\n" );
document.write( "2w^2=648<BR>\n" );
document.write( "w^2=648/2<BR>\n" );
document.write( "w^2=324<BR>\n" );
document.write( "w=18 ft. is the width.<BR>\n" );
document.write( "2*18=36 ft. is the length.<BR>\n" );
document.write( "Proof<BR>\n" );
document.write( "18*36*1/3=216<BR>\n" );
document.write( "648/3=216<BR>\n" );
document.write( "216=216<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );