document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=160097>Question 160097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> measure of angle 1=2x-3 and measure of angle 2 = x +42<BR>\n" );
document.write( "By solving for x, find measure of angle 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118070 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> measure of angle 1=2x-3 and measure of angle 2 = x +42<BR>\n" );
document.write( "By solving for x, find measure of angle 3<BR>\n" );
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document.write( "Call them A, B and C for 1, 2 and 3<BR>\n" );
document.write( "A+B+C = 180<BR>\n" );
document.write( "2x-3 + x+42 + C = 180<BR>\n" );
document.write( "3x + 39 + C = 180<BR>\n" );
document.write( "3x + C = 141<BR>\n" );
document.write( "C = 141 - 3x<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "That's all that can be done without additional info.<BR>\n" );
document.write( "Did you leave something out? </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );