document.write( "Question 159969: Lois rides her bike to visit a friend. She travels at 10 mi/h. While shes there, it starts to rain. Her friend drives her home in a car traveling at 25 mi/h. It takes lois 1.5h longer to to friends than it does to return home.How many hours did it take lois to ride to her friends house? \n" ); document.write( "
Algebra.Com's Answer #118065 by ankor@dixie-net.com(22740)\"\" \"About 
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Lois rides her bike to visit a friend. She travels at 10 mi/h. While shes there,
\n" ); document.write( " it starts to rain. Her friend drives her home in a car traveling at 25 mi/h.
\n" ); document.write( " It takes Lois 1.5h longer to go to friend's house than it does to return home.
\n" ); document.write( "How many hours did it take Lois to ride to her friends house?
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\n" ); document.write( "Let t = time in hrs for reach friend's house
\n" ); document.write( "then
\n" ); document.write( "(t-1.5) = time for friend to drive her home
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\n" ); document.write( "Both trips are the same distance, Write a distance equation from this fact:
\n" ); document.write( "Dist = speed * time
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\n" ); document.write( "Drive dist = Bike dist
\n" ); document.write( "25(t-1.5) = 10t
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\n" ); document.write( "25t - 37.5 = 10t
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\n" ); document.write( "25t - 10t = +37.5
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\n" ); document.write( "15t = 37.5
\n" ); document.write( "t = \"37.5%2F15\"
\n" ); document.write( "t = 2.5 hrs to ride to her friends house
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\n" ); document.write( "Check solution by finding the distances, should be equal:
\n" ); document.write( "10*2.5 = 25 mi
\n" ); document.write( "25*(2.5-1.5) = 25 mi \n" ); document.write( "
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