document.write( "Question 160100: please help me solve this equation\r
\n" ); document.write( "\n" ); document.write( " $\"3c-2d=2\"$
\n" ); document.write( " $\"3c%2B4d=50\"$ \n" ); document.write( "

Algebra.Com's Answer #118064 by Alan3354(69443) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"3c-2d=2\"$
\n" ); document.write( " $\"3c%2B4d=50\"$
\n" ); document.write( "Subtract eqn 2 from eqn 1
\n" ); document.write( "0c - 6d = -48
\n" ); document.write( "d = 8
\n" ); document.write( "Sub into either eqn:
\n" ); document.write( "3c -2*8 = 2
\n" ); document.write( "3c = 18
\n" ); document.write( "c = 6\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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