document.write( "Question 160058: -2x <-8 and x-5 <5
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Algebra.Com's Answer #118036 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"-2x%3C-8\" Start with the first inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E%28-8%29%2F%28-2%29\" Divide both sides by \"-2\" to isolate \"x\". note: Remember, the inequality sign flips when we divide both sides by a negative number. \r
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\n" ); document.write( "\n" ); document.write( "\"x%3E4\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Now let's solve the second inequality \"x-5%3C5\":\r
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\n" ); document.write( "\n" ); document.write( "\"x-5%3C5\" Start with the second inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3C5%2B5\" Add \"5\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3C10\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x%3E4\" and \"x%3C10\"\r
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\n" ); document.write( "\n" ); document.write( "Which combines to the compound inequality \"4%3Cx%3C10\"
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