document.write( "Question 159816: An outboard engine uses a gasoline-oil fuel mixture in the ratio of 15 to 1. How much gasoline must be mixed with a gasoline-oil mixture, which is 75% gasoline, to make 8.0L of the mixture for the outboard engine? \n" ); document.write( "
Algebra.Com's Answer #118028 by ankor@dixie-net.com(22740)\"\" \"About 
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An outboard engine uses a gasoline-oil fuel mixture in the ratio of 15 to 1. How much gasoline must be mixed with a gasoline-oil mixture, which is 75% gasoline, to make 8.0L of the mixture for the outboard engine?
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\n" ); document.write( "Find the percent of gasoline in a 15:1 mixture
\n" ); document.write( "% gasoline = \"15%2F%28%2815%2B1%29%29\" * 100 = 93.75% gasoline
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\n" ); document.write( "Let x = amt of gasoline to accomplish this
\n" ); document.write( "Then
\n" ); document.write( "(8-x) = amt of 75% mixtures used
\n" ); document.write( ":
\n" ); document.write( ".75(8-x) + 1.0x = .9375(8)
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\n" ); document.write( "6 - .75x + 1x = 7.5
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\n" ); document.write( "-.75x + 1x = 7.5 - 6
\n" ); document.write( ":
\n" ); document.write( ".25x = 1.5
\n" ); document.write( ":
\n" ); document.write( "x = \"1.5%2F.25\"
\n" ); document.write( "x = 6 liters of gas required (plus 2 liters of the 75% mixture)
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\n" ); document.write( ":
\n" ); document.write( "Check our solution :
\n" ); document.write( ".75(8-6) + 6 = .9375(8)
\n" ); document.write( ".75(2) + 6 = 7.5
\n" ); document.write( "1.5 + 6 = 7.5
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