document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=160004>Question 160004</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (4/(x+2)) + 3 = (3x/(x-3))\r<BR>\n" );
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document.write( "I do not need to graph, I just need to solve the equation (A rational equation, involving factoring and LCDs) and I am having some problems. The steps that I have are listed below:\r<BR>\n" );
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document.write( "4(x-3) + 3(x+2)(x+3) = 3x(x+2)\r<BR>\n" );
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document.write( "(4x-12)(3x+6)(3x-9) = 3x^2 + 6x\r<BR>\n" );
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document.write( "10x - 15 = 3x^2 + 6x\r<BR>\n" );
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document.write( "0 = 3x^2 - 4x + 15\r<BR>\n" );
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document.write( "I'm not sure if I did this problem correctly but I cannot seem to factor this equation for the correct answer.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117978 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117978\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4(x-3) + 3(x+2)(x+3) = 3x(x+2) Sorry this is wrong (x+3) should be(x-3)\r<BR>\n" );
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document.write( "4(x-3)+3(x+2)(x-3)=3x(x+2)<BR>\n" );
document.write( "4x-12 +3(x^2+2x-3x-6)=3x^2+6X\r<BR>\n" );
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document.write( "Simplify<BR>\n" );
document.write( "4x-12+3(x^2-x-6)=3x^2+6x<BR>\n" );
document.write( "4x-12+3x^2-3x-18=3x^2+6x<BR>\n" );
document.write( "x-12-18+3x^2=3x^2+6x\r<BR>\n" );
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document.write( "x-30+3x^2=3x^2+6x\r<BR>\n" );
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document.write( "subtract 3x^2 from both sides<BR>\n" );
document.write( "x-30=6x\r<BR>\n" );
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document.write( "subtract x from both sides\r<BR>\n" );
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document.write( "-30=5x\r<BR>\n" );
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document.write( "-6=x\r<BR>\n" );
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document.write( "Check answer by replacing x with -6 in the above equation\r<BR>\n" );
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document.write( "-6-6/-6-3=2(-6)/-6-3\r<BR>\n" );
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document.write( "-12/-9=-12/-9\r<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );