document.write( "Question 159939This question is from textbook Algebra 2
\n" ); document.write( ": Brandon goes on a ACaub Scout hike and hikes to a waterfall in 3 hours and hikes back along the same route to the compground in 2 hours. If the hiking rate is 1mph faster returning than going, how fast are the boys hiking each way? \n" ); document.write( "
Algebra.Com's Answer #117942 by ankor@dixie-net.com(22740)\"\" \"About 
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Brandon goes on a a Cub Scout hike and hikes to a waterfall in 3 hours and hikes back along the same route to the campground in 2 hours. If the hiking rate is 1mph faster returning than going, how fast are the boys hiking each way?
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\n" ); document.write( "Let s = hiking rate going
\n" ); document.write( "then
\n" ); document.write( "(s+1) = hiking rate returning
\n" ); document.write( ":
\n" ); document.write( "The distance of each trip is the same. Write a distance equation Dist = time * speed.
\n" ); document.write( ":
\n" ); document.write( "go dist = return dist
\n" ); document.write( "3s = 2(s+1)
\n" ); document.write( "3s = 2s + 2
\n" ); document.write( "3s - 2s = 2
\n" ); document.write( "s = 2 mph is the hiking rate going,
\n" ); document.write( ":
\n" ); document.write( "Obviously, 3 mph is the hiking rate returning
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\n" ); document.write( ":
\n" ); document.write( "Check solution by confirming the distances are the same:
\n" ); document.write( "3*2 = 6 mi
\n" ); document.write( "2*3 = 6 mi \n" ); document.write( "
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