document.write( "Question 159963This question is from textbook Algebra 1
\n" ); document.write( ": At 10:00 am a car leaves a house at a rate of 60mi/hr. At the same time, another car leaves the same house at a rate of 50mi/hr in the opposite direction. At what time will the car be 330 miles apart? \n" ); document.write( "

Algebra.Com's Answer #117938 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "Remember the following eqns:
\n" ); document.write( "Baisc eqn: $\"Speed=distance%2Ftime\"$ , $\"S=d%2Ft\"$
\n" ); document.write( "Also the folowwing eqn we get:
\n" ); document.write( " $\"d=d%5B1%5D%2Bd%5B2%5D\"$ EQN 1
\n" ); document.write( "We are ask for the total time when both cars are 330 miles apart. So,
\n" ); document.write( "As per reference to our basic eqn:
\n" ); document.write( " $\"t=d%2F%28S%5B1%5D%2BS%5B2%5D%29\"$
\n" ); document.write( " $\"t=330mi%2F%2860mi%2Fhr%2B50mi%2Fhr%29=330cross%28mi%29%2F110%28cross%28mi%29%2Fhr%29\"$
\n" ); document.write( " $\"t=3hrs\"$ , ANSWER
\n" ); document.write( "To check, in reference to the basic eqn again:
\n" ); document.write( " $\"d%5B1%5D=S%5B1%5D%2At=60mi%2Fcross%28hr%29%2A3cross%28hrs%29=180miles\"$ Car 1
\n" ); document.write( " $\"d%5B2%5D=S%5B2%5D%2At=50mi%2Fcross%28hr%29%2A3cross%28hrs%29=150miles\"$ Car 2
\n" ); document.write( "Then as per EQN 1:
\n" ); document.write( " $\"d=d%5B1%5D%2Bd%5B2%5D\"$
\n" ); document.write( " $\"330mi=180mi%2B150mi\"$
\n" ); document.write( " $\"330mi=330mi\"$ They are this apart after 3 hours
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo\r
\n" ); document.write( "
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